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Question
Physics
Let F1 be the frequency of second line of Lyman series and F2 be the frequency of first line of Balmer series then frequency of first line of Lyman series is given by
Q. Let
F
1
be the frequency of second line of Lyman series and
F
2
be the frequency of first line of Balmer series then frequency of first line of Lyman series is given by
2350
184
Atoms
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A
F
1
−
F
2
B
F
1
+
F
2
C
F
2
−
F
1
D
F
1
+
F
2
F
1
F
2
Solution:
F
1
=
R
c
[
n
1
2
1
−
n
3
2
1
]
...
(
i
)
F
2
=
R
c
[
n
2
2
1
−
n
3
2
1
]
...
(
ii
)
Subtracting (ii) from (i)
F
=
R
c
[
n
1
2
1
−
n
2
2
1
]
F
=
F
1
−
F
2