Let f:[0,4 π] arrow[0, π] be defined by f(x)= cos -1( cos x). The number of points x ∈[0,4 π] satisfying the equation f(x)=(10-x/10) is

Question

Let f:[0,4 π] arrow[0, π] be defined by f(x)= cos -1( cos x). The number of points x ∈[0,4 π] satisfying the equation f(x)=(10-x/10) is (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

f :[0,4 π] arrow[0, π], f ( x )= cos -1( cos x ) ⇒ point A , B , C satisfy f ( x )=(10- x /10) Hence, 3 points <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/mathematics/d07314a5c94dabc022bc4555def84eb5-.png" />

Q. Let $f : [0, 4 π] \to [0, π]$ be defined by $f (x) = cos^{- 1} (cos x)$ . The number of points $x \in [0, 4 π]$ satisfying the equation $f (x) = \frac{10 - x}{10}$ is____

$f : [0, 4 π] \to [0, π], f (x) = cos^{- 1} (cos x)$
$\Rightarrow$ point $A, B, C$ satisfy $f (x) = \frac{10 - x}{10}$
Hence, $3$ points

Q. Let f:[0,4π]→[0,π] be defined by f(x)=cos−1(cosx). The number of points x∈[0,4π] satisfying the equation f(x)=1010−x​ is____

f:[0,4π]→[0,π],f(x)=cos−1(cosx) ⇒ point A,B,C satisfy f(x)=1010−x​ Hence, 3 points

Q. Let $f : [0, 4 π] \to [0, π]$ be defined by $f (x) = cos^{- 1} (cos x)$ . The number of points $x \in [0, 4 π]$ satisfying the equation $f (x) = \frac{10 - x}{10}$ is____

$f : [0, 4 π] \to [0, π], f (x) = cos^{- 1} (cos x)$
$\Rightarrow$ point $A, B, C$ satisfy $f (x) = \frac{10 - x}{10}$
Hence, $3$ points