Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Mathematics
Let D70= 1,2,5,7,10,14,35,70 . Define '+', ., and '.' by a+b=1 cm(a,b),a.b= gcd (a,b) and a'=(70/a) for all a,b∈ D70 .The value of (2+7) (14.10)' is:
Q. Let
D
70
=
{
1
,
2
,
5
,
7
,
10
,
14
,
35
,
70
}
. Define
′
+
′
,
.
,
and
′
.
′
by
a
+
b
=
1
c
m
(
a
,
b
)
,
a
.
b
=
g
cd
(
a
,
b
)
and
a
′
=
a
70
for all
a
,
b
∈
D
70
.The value of
(
2
+
7
)
(
14.10
)
′
is:
2264
225
KEAM
KEAM 2005
Report Error
A
7
B
14
C
35
D
5
E
1
Solution:
(
2
+
7
)
=
1
c
m
(
2
,
7
)
=
14
and
(
14
−
10
)
=
g
c
d
(
14
,
10
)
=
2
∴
(
14.10
)
=
2
70
=
35
∴
(
2
+
7
)
(
14.10
)
=
14.35
=
g
cd
(
14
,
35
)
=
7