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Tardigrade
Question
Mathematics
Let consider lines (x-3/3)=(y-8/-1)=(z-3/1) and 2 x+5 y-z+47=0=2 x+y+z+7 The shortest distance between both given line is
Q. Let consider lines
3
x
−
3
=
−
1
y
−
8
=
1
z
−
3
and
2
x
+
5
y
−
z
+
47
=
0
=
2
x
+
y
+
z
+
7
The shortest distance between both given line is
28
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A
2
30
21%
B
3
30
64%
C
30
14%
D
75
0%
Solution:
Correct answer is (b)
3
30