Q.
Let binding energy per nucleon of nucleus is denoted by Ebn and radius of nucleus is denoted as r. If mass number of nuclei A,B and 64 and 125 respectively then
r increases with increasing A mass number
So, rA<rB as mass number of A is smaller Ebn decreases with increasing A for A>56, 56Fe has highest Ebn value.
So, Ebn for A=64 is larger as compared to Ebn for nucleus with A=125 EbnA>EbnB