Tangent of parabola y2=4ax is y=mx+ma.......(i)
Where m=tanα
And equation of normal parallel to eq. (i) is y=mx−2am−am3....(ii)
Distance between eq. (i) and (ii) is (1+m2)∣ma+2am+am3∣ =m(1+m2)a(1+m2)2=ma(1+m2)3/2=tanαa(1+(tan)2α)3/2=tanαa(sec)3α =asec2αcosecα