Question

Let $ABCDEF$ be a regular hexagon and $\overrightarrow{AB}=\vec{a},\overrightarrow{BC}=\vec{b},\overrightarrow{CD}=\vec{c}$ then $\overrightarrow{AE}$ is

• A. $\vec{a}+\vec{b}+\vec{c}$
• B. $\vec{b}+\vec{c}$
• C. $\vec{a}+\vec{b}$
• D. $\vec{a}+\vec{c}$

Answer 1

Answer: (B)

$\overrightarrow{AD}=\vec{a}+\vec{b}+\vec{c}$
$\overrightarrow{DE}=-\vec{a}$
$\therefore \overrightarrow{AE}=\overrightarrow{AD}+\overrightarrow{DE}$
(by the rule of vector addition)
$=\vec{b}+\vec{c}$