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Q.
Let $ABCDEF$ be a regular hexagon and $\overrightarrow{AB} = \vec{a}, \overrightarrow{BC}=\vec{b}, \overrightarrow{CD}=\vec{c}$ then $\overrightarrow{AE}$ is
Vector Algebra
Solution:
$\overrightarrow{AD}=\vec{a}+\vec{b}+\vec{c}$
$\overrightarrow{DE}=-\vec{a} $
$\therefore \overrightarrow{AE}=\overrightarrow{AD}+\overrightarrow{DE}$
(by the rule of vector addition)
$=\vec{b}+\vec{c}$