: Let A= x: x is a prime factor of 240 B= x: x is the sum of any two prime factors of 240 . Then

Question

: Let A= x: x is a prime factor of 240 B= x: x is the sum of any two prime factors of 240 . Then (A) 5 ∉ A ∩ B (B) 7 ∈ A ∩ B (C) 8 ∈ A ∩ B (D) 8 ∈ A ∪ B

Tardigrade Admin · Accepted Answer

240=2 × 3 × 5 × 8 So A= 2,3,5 B= 5,7,8 . Clearly 8 ∈ A ∪ B.

Q. : Let $A = {x : x$ is a prime factor of 240 $}$ $B = {x : x$ is the sum of any two prime factors of 240 $}$ . Then

$5 \in / A \cap B$

$7 \in A \cap B$

$8 \in A \cap B$

$8 \in A \cup B$

$240 = 2 \times 3 \times 5 \times 8$
So $A = {2, 3, 5}, B = {5, 7, 8}$ .
Clearly $8 \in A \cup B$ .

Q. : Let A={x:x is a prime factor of 240} B={x:x is the sum of any two prime factors of 240}. Then

5∈/A∩B

7∈A∩B

8∈A∩B

8∈A∪B