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Question
Mathematics
Let A= x: x ∈ R ; x is not a positive integer Define f: A arrow R as f(x)=(2 x/x-1), then f is
Q. Let
A
=
{
x
:
x
∈
R
;
x
is not a positive integer
}
Define
f
:
A
→
R
as
f
(
x
)
=
x
−
1
2
x
, then
f
is
2028
153
KCET
KCET 2021
Relations and Functions - Part 2
Report Error
A
injective but not surjective
20%
B
surjective but not injective
23%
C
bijective
34%
D
neither injective nor suriective
23%
Solution:
f
′
(
x
)
=
(
x
−
1
)
2
−
2
<
0
f
is s.d.
f
is one-one
x
−
1
2
x
=
y
⇒
x
=
y
−
2
y
∈
/
π
for
y
=
2
f
is not out