Tardigrade
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Tardigrade
Question
Mathematics
Let a= underset x arrow 1 textLim (x/ ln x)-(1/x ln x) ; b= underset x arrow 0 textLim (x3-16 x/4 x+x2) ; c= underset x arrow 0 textLim ( ln (1+ sin x)/x) and d= underset x arrow -1 textLim((x+1)3/3( sin (x+1)-(x+1))), then the matrix [a b c d] is
Q. Let
a
=
x
→
1
Lim
l
n
x
x
−
x
l
n
x
1
;
b
=
x
→
0
Lim
4
x
+
x
2
x
3
−
16
x
;
c
=
x
→
0
Lim
x
l
n
(
1
+
s
i
n
x
)
and
d
=
x
→
−
1
Lim
3
(
s
i
n
(
x
+
1
)
−
(
x
+
1
))
(
x
+
1
)
3
, then the matrix
[
a
c
b
d
]
is
150
124
Matrices
Report Error
A
Idempotent
B
Involutary
C
Non singular
D
Nilpotent
Solution:
Correct answer is (d) Nilpotent