Let A = (n, 2n): n ∈ N and B = (2n, 3n): n ∈ N . What is A ∩ B equal to ?

Question

Let A = (n, 2n): n ∈ N and B = (2n, 3n): n ∈ N . What is A ∩ B equal to ? (A) (n, 6n): n ∈ N (B) (2n, 6n): n ∈ N (C) (n, 3n): n ∈ N (D) φ

Tardigrade Admin · Accepted Answer

A = (n, 2n): n ∈ N and B = (2n, 3n): n ∈ N Listing few members of each set A = (1, 2), (2, 4), (3, 6),.... B = (2, 3), (4, 6), (6, 9)...... There is no member common to both these sets, hence. A ∩ B = φ

Q. Let $A = (n, 2 n) : n \in N$ and B = { $(2 n, 3 n) : n \in N$ }. What is A $\cap$ B equal to ?

{ $(n, 6 n) : n \in N$ }

{ $(2 n, 6 n) : n \in N$ }

{ $(n, 3 n) : n \in N$ }

$ϕ$

$A = (n, 2 n) : n \in N$ and B = {(2n, 3n)}: $n \in N$
Listing few members of each set
A = {(1, 2), (2, 4), (3, 6),....}
B = {(2, 3), (4, 6), (6, 9)......}
There is no member common to both these sets, hence.
$A \cap B = ϕ$

Q. Let A=(n,2n):n∈N and B = {(2n,3n):n∈N}. What is A ∩ B equal to ?

{(n,6n):n∈N}

{(2n,6n):n∈N}

{(n,3n):n∈N}

ϕ

A=(n,2n):n∈N and B = {(2n, 3n)}: n∈N Listing few members of each set A = {(1, 2), (2, 4), (3, 6),....} B = {(2, 3), (4, 6), (6, 9)......} There is no member common to both these sets, hence. A∩B=ϕ

Q. Let $A = (n, 2 n) : n \in N$ and B = { $(2 n, 3 n) : n \in N$ }. What is A $\cap$ B equal to ?

{ $(n, 6 n) : n \in N$ }

{ $(2 n, 6 n) : n \in N$ }

{ $(n, 3 n) : n \in N$ }

$ϕ$

$A = (n, 2 n) : n \in N$ and B = {(2n, 3n)}: $n \in N$
Listing few members of each set
A = {(1, 2), (2, 4), (3, 6),....}
B = {(2, 3), (4, 6), (6, 9)......}
There is no member common to both these sets, hence.
$A \cap B = ϕ$