Q.
Let A denotes the Antilog 32(0.8) and B denotes the number of the integers which have the characteristic 4 when the base of log is 5 and C denotes the value of −log7(log379) then unit digit of (A+B+C) is
169
79
Continuity and Differentiability
Report Error
Solution:
A=Antilog32(0.8)=(32)0.8=(25)54=24=16 B=54+1−54=3125−625=2500 C=−log7(log379)=−log7(log39141)=1.
So unit digit of A+B+C is 7