Let A and B be two sets, then (A ∪ B)' ∪(A' ∩ B) is equal to

Question

Let A and B be two sets, then (A ∪ B)' ∪(A' ∩ B) is equal to (A) A ' (B) A (C) B' (D) None of these

Tardigrade Admin · Accepted Answer

Draw the Venn-Euler's diagram and it would be clear that <img class="img-fluid question-image" alt="Solution" src="https://cdn.tardigrade.in/q/nta/m-h7k02xmv8owpdcbo.jpg" /> (A ∪ B) prime ∪(A prime ∩ B)=(A) prime

Q. Let $A$ and $B$ be two sets, then $(A \cup B)^{'} \cup (A^{'} \cap B)$ is equal to

$A^{'}$

$A$

$B^{'}$

None of these

Draw the Venn-Euler's diagram and it would be clear that

$(A \cup B)^{'} \cup (A^{'} \cap B) = (A)^{'}$

Q. Let A and B be two sets, then (A∪B)′∪(A′∩B) is equal to

A′

A

B′

None of these

Draw the Venn-Euler's diagram and it would be clear that (A∪B)′∪(A′∩B)=(A)′

Q. Let $A$ and $B$ be two sets, then $(A \cup B)^{'} \cup (A^{'} \cap B)$ is equal to

$A^{'}$

$A$

$B^{'}$

Draw the Venn-Euler's diagram and it would be clear that

$(A \cup B)^{'} \cup (A^{'} \cap B) = (A)^{'}$