Tardigrade
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Tardigrade
Question
Mathematics
Let, a1 a2, ldots ldots an be a sequence of numbers such that 0 ≤ an ≤ 1 and an-2 an+1+an+2 ≥ 0 for n=1,2,3 ldots ldots Then, range of (n+1)(an-an+1) is
Q. Let,
a
1
a
2
,
……
a
n
be a sequence of numbers such that
0
≤
a
n
≤
1
and
a
n
−
2
a
n
+
1
+
a
n
+
2
≥
0
for
n
=
1
,
2
,
3
……
Then, range of
(
n
+
1
)
(
a
n
−
a
n
+
1
)
is
261
121
Sequences and Series
Report Error
A
(
−
2
,
2
)
B
[
0
,
2
)
C
(
−
2
,
0
]
D
None of these
Solution:
Correct answer is (b)
[
0
,
2
)