1. Tardigrade
  2. Question
  3. Mathematics
  4. Let, a1 a2, ldots ldots an be a sequence of numbers such that 0 ≤ an ≤ 1 and an-2 an+1+an+2 ≥ 0 for n=1,2,3 ldots ldots Then, range of (n+1)(an-an+1) is

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Q. Let, $a_1 a_2, \ldots \ldots a_n$ be a sequence of numbers such that $0 \leq a_n \leq 1$ and $a_n-2 a_{n+1}+a_{n+2} \geq 0$ for $n=1,2,3 \ldots \ldots$ Then, range of $(n+1)\left(a_n-a_{n+1}\right)$ is

Sequences and Series

Solution:

Correct answer is (b) $[0,2)$