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Question
Mathematics
Let a1, a2, a3, ldots ldots, an be in geometric progression. If a1 +a3+a5=455 and a2+a4+a6=1365 then the ratio between each consecutive term is
Q. Let
a
1
,
a
2
,
a
3
,
……
,
a
n
be in geometric progression. If
a
1
+
a
3
+
a
5
=
455
and
a
2
+
a
4
+
a
6
=
1365
then the ratio between each consecutive term is
1720
150
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A
2
B
3
C
4
D
any other number
Solution:
a
+
a
r
2
+
a
r
4
=
455
a
r
+
a
r
3
+
a
r
5
=
1365
⇒
a
(
1
+
r
2
+
r
4
)
a
r
(
1
+
r
2
+
r
4
)
=
455
1365
⇒
r
=
3