Let A= 1,2,3,4 . The number of different unordered pairs (B, C) that can be formed such that B ⊆ A, C ⊆ A and B ∩ C=φ, is

Question

Let A= 1,2,3,4 . The number of different unordered pairs (B, C) that can be formed such that B ⊆ A, C ⊆ A and B ∩ C=φ, is (A) 34 (B) 43 (C) 24 (D) 41

Tardigrade Admin · Accepted Answer

We have, A= 1,2,3,4 Now, B ⊆ A, C ⊆ A and B ∩ C=φ Number of such ordered pairs are 3n A=34

Q. Let $A = {1, 2, 3, 4}$ . The number of different unordered pairs $(B, C)$ that can be formed such that $B \subseteq A, C \subseteq A$ and $B \cap C = ϕ$ , is