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Question

Let 0< P(A)< 1,0< P(B)< 1 P(A ∪ B)=P(A)+P(B)-P(A) . P(B), then: (A) P(B / A)=P(B)-P(A) (B) P(Ac ∪ Bc)=P(Ac)+P(Bc) (C) P (( A ∪ B ) c )= P ( A c ) ⋅ P ( B c ) (D) P(A / B)=P(A)-P(B)

Tardigrade Admin · Accepted Answer

P (( A ∪ B ) c )= P ( A c ) ⋅ P ( B c )

Q. Let $0 < P (A) < 1, 0 < P (B) < 1& P (A \cup B) = P (A) + P (B) - P (A) . P (B)$ , then:

$P (B / A) = P (B) - P (A)$

$P (A^{c} \cup B^{c}) = P (A^{c}) + P (B^{c})$

$P ((A \cup B)^{c}) = P (A^{c}) \cdot P (B^{c})$

$P (A / B) = P (A) - P (B)$

$P ((A \cup B)^{c}) = P (A^{c}) \cdot P (B^{c})$

Q. Let 0<P(A)<1,0<P(B)<1&P(A∪B)=P(A)+P(B)−P(A).P(B), then:

P(B/A)=P(B)−P(A)

P(Ac∪Bc)=P(Ac)+P(Bc)

P((A∪B)c)=P(Ac)⋅P(Bc)

P(A/B)=P(A)−P(B)

P((A∪B)c)=P(Ac)⋅P(Bc)

Q. Let $0 < P (A) < 1, 0 < P (B) < 1& P (A \cup B) = P (A) + P (B) - P (A) . P (B)$ , then:

$P (B / A) = P (B) - P (A)$

$P (A^{c} \cup B^{c}) = P (A^{c}) + P (B^{c})$

$P ((A \cup B)^{c}) = P (A^{c}) \cdot P (B^{c})$

$P (A / B) = P (A) - P (B)$

$P ((A \cup B)^{c}) = P (A^{c}) \cdot P (B^{c})$