Lattice enthalpy and enthalpy of solution of NaCl are 788 kJ mol -1 and 4 kJ mol -1, respectively. The hydration enthalpy of NaCl is :

Question

Lattice enthalpy and enthalpy of solution of NaCl are 788 kJ mol -1 and 4 kJ mol -1, respectively. The hydration enthalpy of NaCl is : (A) -780 kJ mol -1 (B) -784 kJ mol -1 (C) 780 kJ mol -1 (D) 784 kJ mol -1

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/60123670e6e17113975ae2179a92ee93-.png" /> 4=788+Δ H Δ H =-784 kJ

Q. Lattice enthalpy and enthalpy of solution of $N a Cl$ are $788 k J m o l^{- 1}$ and $4 k J$ $m o l^{- 1}$ , respectively. The hydration enthalpy of $N a Cl$ is :

$- 780 k J m o l^{- 1}$

$- 784 k J m o l^{- 1}$

$780 k J m o l^{- 1}$

$784 k J m o l^{- 1}$

$4 = 788 + Δ H$

$Δ H = - 784 k J$

Q. Lattice enthalpy and enthalpy of solution of NaCl are 788kJmol−1 and 4kJ mol−1, respectively. The hydration enthalpy of NaCl is :

−780kJmol−1

−784kJmol−1

780kJmol−1

784kJmol−1