KMnO4 reacts with ferrous ammonium sulphate according to the equation MnO4-+ 5Fe2+ + 8H+ → Mn2++5Fe3+ + 4H2O, here 10 ml of 0.1 M KMnO4 is equivalent to

Question

KMnO4 reacts with ferrous ammonium sulphate according to the equation MnO4-+ 5Fe2+ + 8H+ → Mn2++5Fe3+ + 4H2O, here 10 ml of 0.1 M KMnO4 is equivalent to (A) 20 ml of 0.1 M FeSO4 (B) 30 ml of 0.1 M FeSO4 (C) 40 ml of 0.1 M FeSO4 (D) 50 ml of 0.1 M FeSO4

Tardigrade Admin · Accepted Answer

KMnO4 = Mohr salt (M1V1/n1)=(M2V2/N2);(0.1×10/1)=(M2V2/5);M2V2=5.

Q. $K M n O_{4}$ reacts with ferrous ammonium sulphate according to the equation $M n O_{4}^{-} + 5 F e^{2 +} + 8 H^{+} \to M n^{2 +} + 5 F e^{3 +} + 4 H_{2} O,$ here $10 m l$ of $0.1 M K M n O_{4}$ is equivalent to

$20 m l o f 0.1 M F e S O_{4}$

$30 m l o f 0.1 M F e S O_{4}$

$40 m l o f 0.1 M F e S O_{4}$

$50 m l o f 0.1 M F e S O_{4}$

$K M n O_{4} =$ Mohr salt
$\frac{M _{1} V _{1}}{n _{1}} = \frac{M _{2} V _{2}}{N _{2}}; \frac{0.1 \times 10}{1} = \frac{M _{2} V _{2}}{5}; M_{2} V_{2} = 5.$

Q. KMnO4​ reacts with ferrous ammonium sulphate according to the equation MnO4−​+5Fe2++8H+→Mn2++5Fe3++4H2​O, here 10ml of 0.1MKMnO4​ is equivalent to

20mlof0.1MFeSO4​

30mlof0.1MFeSO4​

40mlof0.1MFeSO4​

50mlof0.1MFeSO4​