Question

Kinetic energy of one mole of an ideal gas at $300K$ is

• A. 3.48 kJ
• B. 3.74 kJ
• C. 37.4 kJ
• D. 34.8 kJ

Answer 1

Answer: (B)

Key Idea The kinetic energy $(KE)$ of the ideal gas is given by
$KE=\frac{3}{2}nRT$
where, $n=$ number of moles
$R=gas$ constant
$T=$ absolute temperature
Here, $n=1$
$T=300K$
$R=8.314Jmo{l}^{-1}{K}^{-1}$
Now put these value in the above equation
$KE=\frac{3}{2}\times 1\times 8.314\times 300$
$=3741.3J$
$=3.74kJ$