Question

Kinetic energy of one mole of an ideal gas at $300K$ is:

• A. 3.48 kJ
• B. 3.74 kJ
• C. 37.4 kJ
• D. 34.8 kJ

Answer 1

Answer: (B)

Given that: $n=1,T=300K$
Now by using: KE (kinetic energy)
$=\frac{3}{2}nRT$
$=\frac{3}{2}\times 1\times 8.314\times 300$
$=3740$ Joule $=3.74kJ$