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Q.
Kinetic energy of one mole of an ideal gas at $300\, K$ is:
Uttarkhand PMTUttarkhand PMT 2004
Solution:
Given that: $n=1, T=300 \,K$
Now by using: KE (kinetic energy)
$=\frac{3}{2} n R T$
$=\frac{3}{2} \times 1 \times 8.314 \times 300$
$=3740$ Joule $=3.74 \,k J$