Kinetic energy of an electron accelerated in a potential difference of 100 V, will be

Question

Kinetic energy of an electron accelerated in a potential difference of 100 V, will be (A)  1.6× 10-21J  (B)  1.6× 10-23J  (C)  1.6× 10-10J  (D)  1.6× 10-16J

Tardigrade Admin · Accepted Answer

Potential difference V= 1000 V The kinetic energy of a electron 1 eV=1.6× 10-19J Hence, the kinetic energy of the electron is =1000 eV =1.6× 10-19× 1000 =1.6× 10-16J

Q. Kinetic energy of an electron accelerated in a potential difference of 100 V, will be

$1.6 \times 10^{- 21} J$

$1.6 \times 10^{- 23} J$

$1.6 \times 10^{- 10} J$

$1.6 \times 10^{- 16} J$

Potential difference V= 1000 V The kinetic energy of a electron $1 e V = 1.6 \times 10^{- 19} J$ Hence, the kinetic energy of the electron is $= 1000 e V$ $= 1.6 \times 10^{- 19} \times 1000$ $= 1.6 \times 10^{- 16} J$

Q. Kinetic energy of an electron accelerated in a potential difference of 100 V, will be

1.6×10−21J

1.6×10−23J

1.6×10−10J

1.6×10−16J

Potential difference V= 1000 V The kinetic energy of a electron 1eV=1.6×10−19J Hence, the kinetic energy of the electron is =1000eV =1.6×10−19×1000 =1.6×10−16J

$1.6 \times 10^{- 21} J$

$1.6 \times 10^{- 23} J$

$1.6 \times 10^{- 10} J$

$1.6 \times 10^{- 16} J$

Potential difference V= 1000 V The kinetic energy of a electron $1 e V = 1.6 \times 10^{- 19} J$ Hence, the kinetic energy of the electron is $= 1000 e V$ $= 1.6 \times 10^{- 19} \times 1000$ $= 1.6 \times 10^{- 16} J$