Kp for the following reaction will be equal to Fe(s) + H2O (g) Fe3O4(s) +H2(g)

Question

Kp for the following reaction will be equal to Fe(s) + H2O (g)<=> Fe3O4(s) +H2(g) (A) ((pH2)4(pFe3O4)/(PFe)3(pH2O)2) (B) ((pH2)/(PH2O)) (C) ((pH2)4/(PH2O)4) (D) ((pH2)(pFe3O4)/(PFe))

Tardigrade Admin · Accepted Answer

Correct answer is (c) ((pH2)4/(PH2O)4)

Q. $K_{p}$ for the following reaction will be equal to
$F e (s) + H_{2} O (g) F e_{3} O_{4} (s) + H_{2} (g)$

$\frac{( p _{H_{2}} ) ^{4} ( p _{F e_{3} O_{4}} )}{( P _{F e} ) ^{3} ( p _{H_{2} O} ) ^{2}}$

$\frac{( p _{H_{2}} )}{( P _{H_{2} O} )}$

$\frac{( p _{H_{2}} ) ^{4}}{( P _{H_{2} O} ) ^{4}}$

$\frac{( p _{H_{2}} ) ( p _{F e_{3} O_{4}} )}{( P _{F e} )}$

Correct answer is (c) $\frac{( p _{H_{2}} ) ^{4}}{( P _{H_{2} O} ) ^{4}}$

Q. Kp​ for the following reaction will be equal to Fe(s)+H2​O(g)​Fe3​O4​(s)+H2​(g)

(PFe​)3(pH2​O​)2(pH2​​)4(pFe3​O4​​)​

(PH2​O​)(pH2​​)​

(PH2​O​)4(pH2​​)4​

(PFe​)(pH2​​)(pFe3​O4​​)​