Kb for weak base B is 1.0× 10- 6 then hydrolysis constant for the reaction B++H2O oversetleftharpoonsBOH+H+ is

Question

Kb for weak base B is 1.0× 10- 6 then hydrolysis constant for the reaction B++H2O oversetleftharpoonsBOH+H+ is (A) 10- 6 (B) 10- 7 (C) 10- 8 (D) 10- 9

Tardigrade Admin · Accepted Answer

B++H2Oleftharpoons BOH+H+ For hydrolysis of B+ the hydrolysis constant can be given as KH=(Kw/Kb) =(1 0- 14/1 0- 6)=10- 8 .

Q. $K_{b}$ for weak base $B$ is $1.0 \times 1 0^{- 6}$ then hydrolysis constant for the reaction
$B^{+} + H_{2} O ⇌ BO H + H^{+}$ is

$1 0^{- 6}$

$1 0^{- 7}$

$1 0^{- 8}$

$1 0^{- 9}$

$B^{+} + H_{2} O ⇌ BO H + H^{+}$
For hydrolysis of $B^{+}$ the hydrolysis constant can be given as
$K_{H} = \frac{K _{w}}{K _{b}}$
$= \frac{1 0 ^{- 14}}{1 0 ^{- 6}} = 1 0^{- 8}$ .

Q. Kb​ for weak base B is 1.0×10−6 then hydrolysis constant for the reaction B++H2​O⇌​BOH+H+ is

10−6

10−7

10−8

10−9