Ka for cyano acetic acid is 4× 10- 4 . Then the degree of hydrolysis of 0.04M sodium cyano acetate solution will be :-

Question

Ka for cyano acetic acid is 4× 10- 4 . Then the degree of hydrolysis of 0.04M sodium cyano acetate solution will be :- (A) 2.5× 10- 8 (B) 0.25× 10- 4 (C) 25× 10- 8 (D) 0.25× 10- 7

Tardigrade Admin · Accepted Answer

h=√(Kw/Ka C)=√(10- 14/4 × 10- 4 × 4 × 10- 2)

Q. $K_{a}$ for cyano acetic acid is $4 \times 1 0^{- 4}$ . Then the degree of hydrolysis of $0.04 M$ sodium cyano acetate solution will be :-

$2.5 \times 1 0^{- 8}$

$0.25 \times 1 0^{- 4}$

$25 \times 1 0^{- 8}$

$0.25 \times 1 0^{- 7}$

$h = \frac{K _{w}}{K _{a} C} = \frac{1 0 ^{- 14}}{4 \times 1 0 ^{- 4} \times 4 \times 1 0 ^{- 2}}$

Q. Ka​ for cyano acetic acid is 4×10−4 . Then the degree of hydrolysis of 0.04M sodium cyano acetate solution will be :-

2.5×10−8

0.25×10−4

25×10−8

0.25×10−7