Joule second is the unit of

Question

Joule second is the unit of (A) momentum (B) angular momentum (C) work (D) pressure

Tardigrade Admin · Accepted Answer

Angular momentum = mvr = kilogram × ( metre / second ) × metre = kilogram × ( ( metre )2 × second / second × second ) = Bigg ( kg × ( ( metre )2 / second2 ) Bigg ) × sec = joule × second

Q. Joule second is the unit of

momentum

angular momentum

work

pressure

Angular momentum = mvr
= $ki l o g r am \times \frac{m e t re}{seco n d} \times m e t re$
= $ki l o g r am \times \frac{( m e t re ) ^{2} \times seco n d}{seco n d \times seco n d}$
= $(k g \times \frac{( m e t re ) ^{2}}{seco n d ^{2}}) \times sec$
= $j o u l e \times seco n d$

Q. Joule second is the unit of

momentum

angular momentum

work

pressure

Angular momentum = mvr = kilogram×secondmetre​×metre = kilogram×second×second(metre)2×second​ = (kg×second2(metre)2​)×sec = joule×second

Angular momentum = mvr
= $ki l o g r am \times \frac{m e t re}{seco n d} \times m e t re$
= $ki l o g r am \times \frac{( m e t re ) ^{2} \times seco n d}{seco n d \times seco n d}$
= $(k g \times \frac{( m e t re ) ^{2}}{seco n d ^{2}}) \times sec$
= $j o u l e \times seco n d$