It takes two seconds to heat water to boiling point using a 10 m length heater coil. What time will it take for the same using 5 m of heater coil connected to the same source:

Question

It takes two seconds to heat water to boiling point using a 10 m length heater coil. What time will it take for the same using 5 m of heater coil connected to the same source: (A) 2 s (B) 3 s (C) 1 s (D) 10.5 s

Tardigrade Admin · Accepted Answer

According to the question, if the length of the heater coil is reduced half, then the resistance also becomes half of the value (E2/R)t1=(E2/R text/2)t2, here t1=2 sec therefore t2=1 sec

Q. It takes two seconds to heat water to boiling point using a 10 m length heater coil. What time will it take for the same using 5 m of heater coil connected to the same source:

2 s

3 s

1 s

10.5 s

According to the question, if the length of the heater coil is reduced half, then the resistance also becomes half of the value $\frac{E ^{2}}{R} t_{1} = \frac{E ^{2}}{R / 2} t_{2},$ here $t_{1} = 2 sec$ therefore $t_{2} = 1 sec$

Q. It takes two seconds to heat water to boiling point using a 10 m length heater coil. What time will it take for the same using 5 m of heater coil connected to the same source:

2 s

3 s

1 s

10.5 s

According to the question, if the length of the heater coil is reduced half, then the resistance also becomes half of the value RE2​t1​=R/2E2​t2​, here t1​=2sec therefore t2​=1sec

According to the question, if the length of the heater coil is reduced half, then the resistance also becomes half of the value $\frac{E ^{2}}{R} t_{1} = \frac{E ^{2}}{R / 2} t_{2},$ here $t_{1} = 2 sec$ therefore $t_{2} = 1 sec$