is the wavelength of photon of energy 35 Kev. h=6.625 × 10-34 J -s, c=3 × 108 m / s , 1 eV =1.6 × 10-19 J.

Question

is the wavelength of photon of energy 35 Kev. h=6.625 × 10-34 J -s, c=3 × 108 m / s , 1 eV =1.6 × 10-19 J. (A) 35 × 10-12 m (B) 35 mathringA (C) 3.5 nm (D) 3.5 mathringA

Tardigrade Admin · Accepted Answer

λ =(hc/Eλ)=(6.625 × 10-34 × 3 × 108/355 × 103 × 1.6 × 10-19) m =0.35 × 10-10 m=3 × 10-12 m

Q. is the wavelength of photon of energy $35 Ke v$ . $h = 6.625 \times 1 0^{- 34} J - s, c = 3 \times 1 0^{8} m / s, 1 e V = 1.6 \times 1 0^{- 19} J$ .

$35 \times 1 0^{- 12} m$

$35 \overset{˚}{A}$

$3.5 nm$

$3.5 \overset{˚}{A}$

$λ = \frac{h _{c}}{E _{λ}} = \frac{6.625 \times 1 0 ^{- 34} \times 3 \times 1 0 ^{8}}{355 \times 1 0 ^{3} \times 1.6 \times 1 0 ^{- 19}} m$
$= 0.35 \times 1 0^{- 10} m = 3 \times 1 0^{- 12} m$

Q. is the wavelength of photon of energy 35Kev. h=6.625×10−34J−s,c=3×108m/s,1eV=1.6×10−19J.

35×10−12m

35A˚

3.5nm

3.5A˚