Ionized hydrogen atoms and α-particles with same momenta enters perpendicular to a constant magnetic field. B. The ratio of their radii of their paths rH: rα will be :

Question

Ionized hydrogen atoms and α-particles with same momenta enters perpendicular to a constant magnetic field. B. The ratio of their radii of their paths rH: rα will be : (A) 4: 1 (B) 1: 4 (C) 2: 1 (D) 1: 2

Tardigrade Admin · Accepted Answer

rH = (p/eB) rα = (p/2eB) (rH/rα ) = ((p/eB)/(p)2eB) (rH/rα) = (2/1)

Q. Ionized hydrogen atoms and $α$ -particles with same momenta enters perpendicular to a constant magnetic field. B. The ratio of their radii of their paths $r_{H} : r_{α}$ will be :

4 : 1

1 : 4

2 : 1

1 : 2

$r_{H} = \frac{p}{e B}$
$r_{α} = \frac{p}{2 e B}$
$\frac{r _{H}}{r _{α}} = \frac{\frac{p}{e B}}{\frac{p}{2 e B}}$
$\frac{r _{H}}{r _{α}} = \frac{2}{1}$

Q. Ionized hydrogen atoms and α-particles with same momenta enters perpendicular to a constant magnetic field. B. The ratio of their radii of their paths rH​:rα​ will be :