Ionisation energy of a hydrogen like species is 54.4 eV. Calculate radius of second bohr orbit of this species.

Question

Ionisation energy of a hydrogen like species is 54.4 eV. Calculate radius of second bohr orbit of this species. (A) 0.529 mathringA (B) 1.058 mathringA (C) 2.116 mathringA (D) 2.106 mathringA

Tardigrade Admin · Accepted Answer

Ionisation energy 13.6 × z2=54.4 ∴ Z =2 r =0.529 ( n 2/ z ) mathringA=0.529× (22/2)=1.058 mathringA

Q. Ionisation energy of a hydrogen like species is $54.4 e V$ . Calculate radius of second bohr orbit of this species.

$0.529 \overset{˚}{A}$

$1.058 \overset{˚}{A}$

$2.116 \overset{˚}{A}$

$2.106 \overset{˚}{A}$

Ionisation energy $13.6 \times z^{2} = 54.4$
$∴ Z = 2$
$r = 0.529 \frac{n ^{2}}{z} \overset{˚}{A} = 0.529 \times \frac{2 ^{2}}{2} = 1.058 \overset{˚}{A}$

Q. Ionisation energy of a hydrogen like species is 54.4eV. Calculate radius of second bohr orbit of this species.

0.529A˚

1.058A˚

2.116A˚

2.106A˚