Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Chemistry
Ionic strength of 0.2 M Na 3 PO 4 is
Q. Ionic strength of
0.2
M
N
a
3
P
O
4
is
87
156
Electrochemistry
Report Error
A
2.8
B
1.2
C
1.0
D
1.8
Solution:
[
N
a
⊕
]
=
0.6
M
[
P
O
4
3
−
]
=
0.2
μ
=
2
1
[
0.6
(
1
)
2
+
0.2
(
3
)
2
]
=
1.2