Iodine reacts with hot cone, solution of NaOH to give

Question

Iodine reacts with hot cone, solution of NaOH to give (A) Nal + NaOI + O2 (B) Nal + HIO + O3 (C) Nal + NaIO3 + H2O (D) Nal + HIO3 + H2O

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/df890971ced1b586e3ccc746263df01e-.png" /> With cold dilute solution, the reaction is I2+N a O H arrow N a I+H I O

Q. Iodine reacts with hot cone, solution of NaOH to give

$N a l + N a O I + O_{2}$

$N a l + H I O + O_{3}$

$N a l + N a I O_{3} + H_{2} O$

$N a l + H I O_{3} + H_{2} O$

With cold dilute solution, the reaction is $I_{2} + N a O H \to N a I + H I O$

Q. Iodine reacts with hot cone, solution of NaOH to give

Nal+NaOI+O2​

Nal+HIO+O3​

Nal+NaIO3​+H2​O

Nal+HIO3​+H2​O

With cold dilute solution, the reaction is I2​+NaOH→NaI+HIO

$N a l + N a O I + O_{2}$

$N a l + H I O + O_{3}$

$N a l + N a I O_{3} + H_{2} O$

$N a l + H I O_{3} + H_{2} O$

With cold dilute solution, the reaction is $I_{2} + N a O H \to N a I + H I O$