Intermolecular forces between n-hexane and n-heptane are nearly same as between hexane and heptane individually. When these two are mixed, which of the following is not true about the solution formed ?

Question

Intermolecular forces between n-hexane and n-heptane are nearly same as between hexane and heptane individually. When these two are mixed, which of the following is not true about the solution formed ? (A) It obeys Raoult’s law, i.e. pA = xAp°A and pB = xBp°B (B) Δ Hmixing is zero (C) Δ Vmixing is zero (D) It forms minimum boiling azeotrope

Tardigrade Admin · Accepted Answer

Azeotropes are formed by the solutions which show deviations from ideal behaviour.

Q. Intermolecular forces between $n$ -hexane and $n$ -heptane are nearly same as between hexane and heptane individually. When these two are mixed, which of the following is not true about the solution formed ?

It obeys Raoult’s law, i.e. $p_{A} = x_{A} p_{A}^{\circ}$ and $p_{B} = x_{B} p_{B}^{\circ}$

$Δ H_{mi x in g}$ is zero

$Δ V_{mi x in g}$ is zero

It forms minimum boiling azeotrope

Azeotropes are formed by the solutions which show deviations from ideal behaviour.

Q. Intermolecular forces between n-hexane and n-heptane are nearly same as between hexane and heptane individually. When these two are mixed, which of the following is not true about the solution formed ?

It obeys Raoult’s law, i.e. pA​=xA​pA∘​ and pB​=xB​pB∘​

ΔHmixing​ is zero

ΔVmixing​ is zero

It forms minimum boiling azeotrope

Azeotropes are formed by the solutions which show deviations from ideal behaviour.

Q. Intermolecular forces between $n$ -hexane and $n$ -heptane are nearly same as between hexane and heptane individually. When these two are mixed, which of the following is not true about the solution formed ?

It obeys Raoult’s law, i.e. $p_{A} = x_{A} p_{A}^{\circ}$ and $p_{B} = x_{B} p_{B}^{\circ}$

$Δ H_{mi x in g}$ is zero

$Δ V_{mi x in g}$ is zero