Question

$\int \left(\frac{x-1}{x^2}\right)e^{x}dx$ is equal to:

• A. $e^x+\frac{1}{x}+c$
• B. $\frac{e^x}{x}+c$
• C. $\frac{e^x}{x^2}+c$
• D. $e^x(\log x+\frac{1}{x})+c$

Answer 1

Answer: (B)

Correct answer is (b) $\frac{e^x}{x}+c$