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Question
Mathematics
∫ sec 3 x dx
Q.
∫
sec
3
x
d
x
1355
217
J & K CET
J & K CET 2014
Integrals
Report Error
A
1/2
[
sec
x
tan
x
−
lo
g
∣
sec
x
+
tan
x
∣
]
+
C
14%
B
1/2
[
sec
x
tan
x
+
lo
g
∣
sec
x
−
tan
x
∣
]
+
C
23%
C
1/2
[
sec
x
tan
x
−
lo
g
∣
sec
x
−
tan
x
∣
]
+
C
11%
D
1/2
[
sec
x
tan
x
+
lo
g
∣
sec
x
+
tan
x
∣
]
+
C
52%
Solution:
Let
I
=
∫
sec
3
x
d
x
=
∫
I
sec
x
II
sec
2
x
d
x
sec
x
tan
x
−
∫
sec
x
t
a
n
2
x
d
x
(using integration by parts)
=
sec
x
tan
x
−
∫
sec
x
(
sec
2
x
−
1
)
d
x
⇒
I
=
sec
x
tan
x
−
∫
sec
3
x
d
x
+
∫
sec
x
d
x
⇒
I
=
sec
x
tan
x
−
I
+
lo
g
∣
sec
x
+
t
an
x
∣
+
2
C
⇒
2
I
=
sec
x
tan
x
+
lo
g
∣
sec
x
+
tan
x
∣
+
2
C
⇒
I
=
2
1
[
sec
x
tan
x
+
lo
g
∣
sec
x
+
tan
x
∣
]
+
C