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Tardigrade
Question
Mathematics
∫ limits0 ln 5 ( e x √ e x -1/ e x +3) dx =
Q.
0
∫
l
n
5
e
x
+
3
e
x
e
x
−
1
d
x
=
36
118
Integrals
Report Error
A
4
−
π
25%
B
6
−
π
8%
C
5
−
π
42%
D
None
25%
Solution:
put
e
x
−
1
=
t
2