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Question
Mathematics
∫ (d x/√[3]x5 / 2(x+1)7 / 2)
Q.
∫
3
x
5/2
(
x
+
1
)
7/2
d
x
316
140
Integrals
Report Error
A
−
(
x
x
+
1
)
1/6
+
C
B
6
(
x
x
+
1
)
−
1/6
+
C
C
(
x
+
1
x
)
5/6
+
C
D
−
(
x
+
1
x
)
5/6
+
C
Solution:
∫
[
x
6
(
1
+
x
1
)
7/2
]
1/3
d
x
=
∫
x
2
(
1
+
x
1
)
7/6
d
x
now put
1
+
x
1
=
t
6