∫ √ (cosx-cos3x /1-cos3x) dx=

Question

∫ √ (cosx-cos3x /1-cos3x) dx=  (A) - (2/3) sin-1 (cos 3/2x)+c (B)  (2/3) cos-1 (cos 3/2x)+c (C)  (2/3) sin-1 (cos 3/2x)+c (D)  (3/2) cos-1 (cos 3/2x)+c

Tardigrade Admin · Accepted Answer

Correct answer is (a) - (2/3) sin-1 (cos 3/2x)+c

Q. $\int \frac{cos x - co s ^{3 x}}{1 - co s ^{3} x} d x =$

$- \frac{2}{3} s i n^{- 1} (co s^{3/2} x) + c$

$\frac{2}{3} co s^{- 1} (co s^{3/2} x) + c$

$\frac{2}{3} s i n^{- 1} (co s^{3/2} x) + c$

$\frac{3}{2} co s^{- 1} (co s^{3/2} x) + c$

Correct answer is (a) $- \frac{2}{3} s i n^{- 1} (co s^{3/2} x) + c$

Q. ∫1−cos3xcosx−cos3x​​dx=

−32​sin−1(cos3/2x)+c

32​cos−1(cos3/2x)+c

32​sin−1(cos3/2x)+c

23​cos−1(cos3/2x)+c

Correct answer is (a) −32​sin−1(cos3/2x)+c

Q. $\int \frac{cos x - co s ^{3 x}}{1 - co s ^{3} x} d x =$

$- \frac{2}{3} s i n^{- 1} (co s^{3/2} x) + c$

$\frac{2}{3} co s^{- 1} (co s^{3/2} x) + c$

$\frac{2}{3} s i n^{- 1} (co s^{3/2} x) + c$

$\frac{3}{2} co s^{- 1} (co s^{3/2} x) + c$

Correct answer is (a) $- \frac{2}{3} s i n^{- 1} (co s^{3/2} x) + c$