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Tardigrade
Question
Mathematics
∫ ( 1 + 2x + 3x2 + 4x3 + .... ) dx =
Q.
∫
(
1
+
2
x
+
3
x
2
+
4
x
3
+
....
)
d
x
=
3465
210
Integrals
Report Error
A
(
1
+
x
)
−
1
+
c
25%
B
(
1
−
x
)
−
1
+
c
47%
C
(
1
−
x
)
−
1
−
1
+
c
14%
D
None to these
14%
Solution:
∫
(
1
+
2
x
+
3
x
2
+
4
x
3
+
....
)
d
x
∫
(
1
+
x
)
−
2
d
x
=
(
1
−
x
)
−
1
+
c