∫-11(17x5-x4+29x3-31x+1/x2+1)dx is

Question

∫-11(17x5-x4+29x3-31x+1/x2+1)dx is (A) 4/5 (B) 5/4 (C) 4/3 (D) 3/4

Tardigrade Admin · Accepted Answer

Let I=∫-11(17x5-x4+28x3-31x+1/x2+1)dx I=∫-11(17x5+29x3-31x/x2+1)dx-∫-11(x4-1/x2+1)dx =-2∫01((x2-1)(x2+1)/(x2+1))dx =2[ ( (x3/3)-x ) ]01=-2[ (1/3)-1 ] =(4/3)

Q. $\int_{- 1}^{1} \frac{17 x ^{5} - x ^{4} + 29 x ^{3} - 31 x + 1}{x ^{2} + 1} d x$ is

4/5

5/4

4/3

3/4

2/3

Q. ∫−11​x2+117x5−x4+29x3−31x+1​dx is

4/5

5/4

4/3

3/4

2/3

Let I=∫−11​x2+117x5−x4+28x3−31x+1​dx I=∫−11​x2+117x5+29x3−31x​dx−∫−11​x2+1x4−1​dx =−2∫01​(x2+1)(x2−1)(x2+1)​dx =2[(3x3​−x)]01​=−2[31​−1] =34​

Q. $\int_{- 1}^{1} \frac{17 x ^{5} - x ^{4} + 29 x ^{3} - 31 x + 1}{x ^{2} + 1} d x$ is