Instantaneous displacement current of 1.0 A in the space between the parallel plates of 1 μ F capacitor can be established , by rate of change of potential difference

Question

Instantaneous displacement current of 1.0 A in the space between the parallel plates of 1 μ F capacitor can be established , by rate of change of potential difference (A) 105 V s-1 (B) 106 V s-1 (C) 104 V s-1 (D) 107 V s-1

Tardigrade Admin · Accepted Answer

Id=ε0 (dφE/dt)=ε0A (d/dt)((V/d)) or Id=(ε0A/d)×(dV/dt)=C (dV/dt) or (dV/dt)=(Id/C)=(1.0/10-6)=106 V s-1

Q. Instantaneous displacement current of 1.0 A in the space between the parallel plates of $1 μ F$ capacitor can be established , by rate of change of potential difference

$1 0^{5} V s^{- 1}$

$1 0^{6} V s^{- 1}$

$1 0^{4} V s^{- 1}$

$1 0^{7} V s^{- 1}$

$I_{d} = ε_{0} \frac{d ϕ _{E}}{d t} = ε_{0} A \frac{d}{d t} (\frac{V}{d})$
or $I_{d} = \frac{ε _{0} A}{d} \times \frac{d V}{d t} = C \frac{d V}{d t}$ or $\frac{d V}{d t} = \frac{I _{d}}{C} = \frac{1.0}{1 0 ^{- 6}} = 1 0^{6} V s^{- 1}$

Q. Instantaneous displacement current of 1.0 A in the space between the parallel plates of 1μF capacitor can be established , by rate of change of potential difference

105Vs−1

106Vs−1

104Vs−1

107Vs−1