Initially mass m is held such that spring is in relaxed condition. If mass m is suddenly released, maximum elongation in spring will be

Question

Initially mass m is held such that spring is in relaxed condition. If mass m is suddenly released, maximum elongation in spring will be (A) (m g/k) (B) (2 m g/k) (C) (m g/2 k) (D) (m g/4 k)

Tardigrade Admin · Accepted Answer

Ei=Ef ⇒ 0=-m g x+(1/2) k x2 x=(2 m g/k)

Q. Initially mass $m$ is held such that spring is in relaxed condition. If mass $m$ is suddenly released, maximum elongation in spring will be

$\frac{m g}{k}$

$\frac{2 m g}{k}$

$\frac{m g}{2 k}$

$\frac{m g}{4 k}$

$E_{i} = E_{f}$
$\Rightarrow 0 = - m gx + \frac{1}{2} k x^{2}$
$x = \frac{2 m g}{k}$

Q. Initially mass m is held such that spring is in relaxed condition. If mass m is suddenly released, maximum elongation in spring will be

kmg​

k2mg​

2kmg​

4kmg​