In Youngs double slit experiment, the slits are 3 mm apart. The wavelength of light used is 5000 text overseto mathop textA and the distance between the slits and the screen is 90 cm. The fringe width in mm is

Question

In Youngs double slit experiment, the slits are 3 mm apart. The wavelength of light used is 5000 text overseto mathop textA and the distance between the slits and the screen is 90 cm. The fringe width in mm is (A) 1.5 (B) 0.015 (C) 2.0 (D) 0.15

Tardigrade Admin · Accepted Answer

Let λ be wavelength of monochromatic light, used to illuminate the slit 5, and d be the distance between coherent sources, then width of slits is given by where D is distance between screen and source. Given, d=3 text mm, text λ =5000 text overseto mathop textA =5× 10-7m =5× 10-4mm, D=90 text cm=900 text mm. ∴ W=(5× 10-4× 900/3)=15× 10-2mm =0.15 text mm

Q. In Youngs double slit experiment, the slits are 3 mm apart. The wavelength of light used is 5000Ao and the distance between the slits and the screen is 90 cm. The fringe width in mm is

1.5

0.015

2.0

0.15

Q. In Youngs double slit experiment, the slits are 3 mm apart. The wavelength of light used is $5000 A o$ and the distance between the slits and the screen is 90 cm. The fringe width in mm is