In Young's experiment the wavelength of red light is 7.8 × 10-5 cm and that of blue light is 5.2 × 10-5 cm. the value of 'n for which (n+1) th blue bright band coincides with n t h red bright band is

Question

In Young's experiment the wavelength of red light is 7.8 × 10-5 cm and that of blue light is 5.2 × 10-5 cm. the value of 'n for which (n+1) th blue bright band coincides with n t h red bright band is (A) 4 (B) 3 (C) 2 (D) 1

Tardigrade Admin · Accepted Answer

(n+1) 5.2 × 10-5=n × 7.8 × 10-5 ⇒ 4(n+1)=6 n ⇒ 2 n=4 ⇒ n=2

Q. In Young's experiment the wavelength of red light is $7.8 \times 1 0^{- 5} c m$ and that of blue light is $5.2 \times 1 0^{- 5} c m$ . the value of ' $n$ for which $(n + 1)$ th blue bright band coincides with $n t h$ red bright band is

4

3

2

1

$(n + 1) 5.2 \times 1 0^{- 5} = n \times 7.8 \times 1 0^{- 5}$
$\Rightarrow 4 (n + 1) = 6 n$
$\Rightarrow 2 n = 4 \Rightarrow n = 2$

Q. In Young's experiment the wavelength of red light is 7.8×10−5cm and that of blue light is 5.2×10−5cm. the value of 'n for which (n+1) th blue bright band coincides with nth red bright band is

4

3

2

1

(n+1)5.2×10−5=n×7.8×10−5 ⇒4(n+1)=6n ⇒2n=4⇒n=2

Q. In Young's experiment the wavelength of red light is $7.8 \times 1 0^{- 5} c m$ and that of blue light is $5.2 \times 1 0^{- 5} c m$ . the value of ' $n$ for which $(n + 1)$ th blue bright band coincides with $n t h$ red bright band is

$(n + 1) 5.2 \times 1 0^{- 5} = n \times 7.8 \times 1 0^{- 5}$
$\Rightarrow 4 (n + 1) = 6 n$
$\Rightarrow 2 n = 4 \Rightarrow n = 2$