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Physics
In Young's double slits experiment, the position of 5 text th bright fringe from the central maximum is 5 cm. The distance between slits and screen is 1 m and wavelength of used monochromatic light is 600 mm. The separation between the slits is:
Q. In Young's double slits experiment, the position of
5
th
bright fringe from the central maximum is
5
c
m
. The distance between slits and screen is
1
m
and wavelength of used monochromatic light is
600
mm
. The separation between the slits is:
277
123
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A
12
μ
m
5%
B
60
μ
m
80%
C
36
μ
m
15%
D
48
μ
m
0%
Solution:
Given
D
=
1
m
λ
=
600
×
1
0
−
9
m
n
=
5
As
y
n
t
h
=
d
nλ
D
⇒
d
5
×
600
×
1
0
−
9
×
1
=
5
×
1
0
−
2
⇒
d
=
5
×
1
0
−
2
5
×
600
×
1
0
−
9
×
1
=
60
×
1
0
−
6
m
⇒
d
=
60
μ
m