In young's double slit experiment, the fringe width is 12 mm. If the entire arrangement is placed in water of refractive index (4/3), then the fringe width becomes (in mm )

Question

In young's double slit experiment, the fringe width is 12 mm. If the entire arrangement is placed in water of refractive index (4/3), then the fringe width becomes (in mm ) (A) 16 (B) 9 (C) 48 (D) 12

Tardigrade Admin · Accepted Answer

For a given light wavelength corresponding a medium of refractive index = and we know that fringe width Therefore, β text med = =(12/ underline4)=9 mm

Q. In young's double slit experiment, the fringe width is $12 mm$ . If the entire arrangement is placed in water of refractive index $\frac{4}{3}$ , then the fringe width becomes (in $mm$ )

16

9

48

12

For a given light wavelength corresponding a medium of refractive index
$=$ _____
and we know that fringe width
Therefore, $β_{med} =$ _____ $= \frac{12}{4} = 9 mm$

Q. In young's double slit experiment, the fringe width is 12mm. If the entire arrangement is placed in water of refractive index 34​, then the fringe width becomes (in mm )

16

9

48

12

For a given light wavelength corresponding a medium of refractive index =_________ and we know that fringe width ____ Therefore, βmed ​= _____ =4​12​=9mm

Q. In young's double slit experiment, the fringe width is $12 mm$ . If the entire arrangement is placed in water of refractive index $\frac{4}{3}$ , then the fringe width becomes (in $mm$ )

For a given light wavelength corresponding a medium of refractive index
$=$ _____
and we know that fringe width
Therefore, $β_{med} =$ _____ $= \frac{12}{4} = 9 mm$