In Young's double slit experiment, the constant phase difference between two sources is (π/2). The intensity at a point equidistant from the slits in terms of maximum intensity I0 is.

Question

In Young's double slit experiment, the constant phase difference between two sources is (π/2). The intensity at a point equidistant from the slits in terms of maximum intensity I0 is. (A) I0 (B) I0/2 (C) 3I0/4 (D) 3 I0

Tardigrade Admin · Accepted Answer

I = I0 cos2 ( (θ/2) ) I = I0 cos2 ( (π/4) )

Q. In Young's double slit experiment, the constant phase difference between two sources is $\frac{π}{2}$ . The intensity at a point equidistant from the slits in terms of maximum intensity $I_{0}$ is.

$I_{0}$

$I_{0} /2$

$3 I_{0} /4$

$3 I_{0}$

$I = I_{0} co s^{2} (\frac{θ}{2})$
$I = I_{0} co s^{2} (\frac{π}{4})$

Q. In Young's double slit experiment, the constant phase difference between two sources is 2π​. The intensity at a point equidistant from the slits in terms of maximum intensity I0​ is.

I0​

I0​/2

3I0​/4

3I0​